211404330131 has 2 divisors, whose sum is σ = 211404330132. Its totient is φ = 211404330130.

The previous prime is 211404330113. The next prime is 211404330133. The reversal of 211404330131 is 131033404112.

Together with previous prime (211404330113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211404330131 is a prime.

It is a super-2 number, since 2×211404330131² (a number of 23 digits) contains 22 as substring.

Together with 211404330133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 211404330097 and 211404330106.

It is not a weakly prime, because it can be changed into another prime (211404330133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105702165065 + 105702165066.

It is an arithmetic number, because the mean of its divisors is an integer number (105702165066).

Almost surely, 2^211404330131 is an apocalyptic number.

211404330131 is a deficient number, since it is larger than the sum of its proper divisors (1).

211404330131 is an equidigital number, since it uses as much as digits as its factorization.

211404330131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 211404330131 its reverse (131033404112), we get a palindrome (342437734243).

The spelling of 211404330131 in words is "two hundred eleven billion, four hundred four million, three hundred thirty thousand, one hundred thirty-one".