2114043310231 has 4 divisors (see below), whose sum is σ = 2153930919912. Its totient is φ = 2074155700552.

The previous prime is 2114043310207. The next prime is 2114043310279. The reversal of 2114043310231 is 1320133404112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2114043310231 - 2¹¹ = 2114043308183 is a prime.

It is a super-2 number, since 2×2114043310231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2114043310196 and 2114043310205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2114043310931) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19943804761 + ... + 19943804866.

It is an arithmetic number, because the mean of its divisors is an integer number (538482729978).

Almost surely, 2^{2114043310231} is an apocalyptic number.

2114043310231 is a deficient number, since it is larger than the sum of its proper divisors (39887609681).

2114043310231 is an equidigital number, since it uses as much as digits as its factorization.

2114043310231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39887609680.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 2114043310231 its reverse (1320133404112), we get a palindrome (3434176714343).

The spelling of 2114043310231 in words is "two trillion, one hundred fourteen billion, forty-three million, three hundred ten thousand, two hundred thirty-one".