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21140501 is a prime number
BaseRepresentation
bin101000010100…
…1010000010101
31110210001022112
41100221100111
520402444001
62033040405
7344456054
oct120512025
943701275
1021140501
1110a2a198
1270b6105
1344c2595
142b4439b
151cc8cbb
hex1429415

21140501 has 2 divisors, whose sum is σ = 21140502. Its totient is φ = 21140500.

The previous prime is 21140423. The next prime is 21140513. The reversal of 21140501 is 10504112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14432401 + 6708100 = 3799^2 + 2590^2 .

It is a cyclic number.

It is not a de Polignac number, because 21140501 - 222 = 16946197 is a prime.

It is a Chen prime.

It is a zygodrome in base 4.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21140201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10570250 + 10570251.

It is an arithmetic number, because the mean of its divisors is an integer number (10570251).

Almost surely, 221140501 is an apocalyptic number.

It is an amenable number.

21140501 is a deficient number, since it is larger than the sum of its proper divisors (1).

21140501 is an equidigital number, since it uses as much as digits as its factorization.

21140501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40, while the sum is 14.

The square root of 21140501 is about 4597.8800549819. The cubic root of 21140501 is about 276.5063387787.

Adding to 21140501 its reverse (10504112), we get a palindrome (31644613).

The spelling of 21140501 in words is "twenty-one million, one hundred forty thousand, five hundred one".