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21140525140439 is a prime number
BaseRepresentation
bin1001100111010001010010…
…11111011100100111010111
32202212000101112201201010212
410303220221133130213113
510232331243413443224
6112543453450040035
74311231630532625
oct463505137344727
982760345651125
1021140525140439
116810712344931
12245521311901b
13ba4709b89743
145312c7950515
15269da84a0d0e
hex133a297dc9d7

21140525140439 has 2 divisors, whose sum is σ = 21140525140440. Its totient is φ = 21140525140438.

The previous prime is 21140525140313. The next prime is 21140525140463. The reversal of 21140525140439 is 93404152504112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21140525140439 - 224 = 21140508363223 is a prime.

It is a super-2 number, since 2×211405251404392 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21140525140396 and 21140525140405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21140525140939) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10570262570219 + 10570262570220.

It is an arithmetic number, because the mean of its divisors is an integer number (10570262570220).

Almost surely, 221140525140439 is an apocalyptic number.

21140525140439 is a deficient number, since it is larger than the sum of its proper divisors (1).

21140525140439 is an equidigital number, since it uses as much as digits as its factorization.

21140525140439 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 172800, while the sum is 41.

The spelling of 21140525140439 in words is "twenty-one trillion, one hundred forty billion, five hundred twenty-five million, one hundred forty thousand, four hundred thirty-nine".