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21140534041313 is a prime number
BaseRepresentation
bin1001100111010001010100…
…00001011001101011100001
32202212000102011110220211212
410303220222001121223201
510232331303203310223
6112543454404515505
74311232066303661
oct463505201315341
982760364426755
1021140534041313
116810717374225
1224552160abb95
13ba470b984c2b
145312c8bca1a1
15269da915d278
hex133a2a059ae1

21140534041313 has 2 divisors, whose sum is σ = 21140534041314. Its totient is φ = 21140534041312.

The previous prime is 21140534041307. The next prime is 21140534041339. The reversal of 21140534041313 is 31314043504112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13469362423969 + 7671171617344 = 3670063^2 + 2769688^2 .

It is a cyclic number.

It is not a de Polignac number, because 21140534041313 - 232 = 21136239074017 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 21140534041313.

It is not a weakly prime, because it can be changed into another prime (21140534041373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10570267020656 + 10570267020657.

It is an arithmetic number, because the mean of its divisors is an integer number (10570267020657).

Almost surely, 221140534041313 is an apocalyptic number.

It is an amenable number.

21140534041313 is a deficient number, since it is larger than the sum of its proper divisors (1).

21140534041313 is an equidigital number, since it uses as much as digits as its factorization.

21140534041313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 21140534041313 its reverse (31314043504112), we get a palindrome (52454577545425).

The spelling of 21140534041313 in words is "twenty-one trillion, one hundred forty billion, five hundred thirty-four million, forty-one thousand, three hundred thirteen".