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211410133100 = 22522114101331
BaseRepresentation
bin1100010011100100000…
…1101010000001101100
3202012200112110111120122
43010321001222001230
511430431443224400
6241042004504112
721162640324115
oct3047101520154
9665615414518
10211410133100
1181727566071
1234b809ab038
1316c221c541a
14a33763320c
155775029685
hex313906a06c

211410133100 has 18 divisors (see below), whose sum is σ = 458759989044. Its totient is φ = 84564053200.

The previous prime is 211410133093. The next prime is 211410133141. The reversal of 211410133100 is 1331014112.

It is a super-2 number, since 2×2114101331002 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1057050566 + ... + 1057050765.

It is an arithmetic number, because the mean of its divisors is an integer number (25486666058).

Almost surely, 2211410133100 is an apocalyptic number.

211410133100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

211410133100 is an abundant number, since it is smaller than the sum of its proper divisors (247349855944).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

211410133100 is a wasteful number, since it uses less digits than its factorization.

211410133100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2114101345 (or 2114101338 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 211410133100 its reverse (1331014112), we get a palindrome (212741147212).

The spelling of 211410133100 in words is "two hundred eleven billion, four hundred ten million, one hundred thirty-three thousand, one hundred".

Divisors: 1 2 4 5 10 20 25 50 100 2114101331 4228202662 8456405324 10570506655 21141013310 42282026620 52852533275 105705066550 211410133100