Base | Representation |
---|---|
bin | 11110110000111010100… |
… | …000001110001110101011 |
3 | 21111002212122100112111012 |
4 | 132300322200032032223 |
5 | 234114141442410201 |
6 | 4255112344254135 |
7 | 305511334461641 |
oct | 36607240161653 |
9 | 7432778315435 |
10 | 2114105435051 |
11 | 745650449025 |
12 | 2a188977134b |
13 | 12448947a28c |
14 | 74474dd1191 |
15 | 39ed57255bb |
hex | 1ec3a80e3ab |
2114105435051 has 2 divisors, whose sum is σ = 2114105435052. Its totient is φ = 2114105435050.
The previous prime is 2114105435017. The next prime is 2114105435107. The reversal of 2114105435051 is 1505345014112.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2114105435051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2114105434999 and 2114105435017.
It is not a weakly prime, because it can be changed into another prime (2114105435251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057052717525 + 1057052717526.
It is an arithmetic number, because the mean of its divisors is an integer number (1057052717526).
Almost surely, 22114105435051 is an apocalyptic number.
2114105435051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2114105435051 is an equidigital number, since it uses as much as digits as its factorization.
2114105435051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12000, while the sum is 32.
The spelling of 2114105435051 in words is "two trillion, one hundred fourteen billion, one hundred five million, four hundred thirty-five thousand, fifty-one".
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