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211411040407 = 759214958229
BaseRepresentation
bin1100010011100100010…
…1000111100010010111
3202012200121011121011121
43010321011013202113
511430432211243112
6241042040144411
721162651123250
oct3047105074227
9665617147147
10211411040407
1181728025806
1234b81168107
1316c224523a8
14a3377cbb27
155775158407
hex3139147897

211411040407 has 24 divisors (see below), whose sum is σ = 247430916000. Its totient is φ = 176939519808.

The previous prime is 211411040387. The next prime is 211411040431. The reversal of 211411040407 is 704040114112.

It is a de Polignac number, because none of the positive numbers 2k-211411040407 is a prime.

It is a super-6 number, since 6×2114110404076 (a number of 69 digits) contains 666666 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211411040437) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3601569 + ... + 3659797.

It is an arithmetic number, because the mean of its divisors is an integer number (10309621500).

Almost surely, 2211411040407 is an apocalyptic number.

211411040407 is a deficient number, since it is larger than the sum of its proper divisors (36019875593).

211411040407 is an equidigital number, since it uses as much as digits as its factorization.

211411040407 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58503 (or 58444 counting only the distinct ones).

The product of its (nonzero) digits is 896, while the sum is 25.

Adding to 211411040407 its reverse (704040114112), we get a palindrome (915451154519).

The spelling of 211411040407 in words is "two hundred eleven billion, four hundred eleven million, forty thousand, four hundred seven".

Divisors: 1 7 59 149 413 1043 3481 8791 24367 58229 61537 407603 518669 3435511 3630683 8676121 24048577 60732847 202695149 511891139 1418866043 3583237973 30201577201 211411040407