Base | Representation |
---|---|
bin | 10011101100000110… |
… | …111111010110000011 |
3 | 2000120100202101202111 |
4 | 103230012333112003 |
5 | 321244111440413 |
6 | 13413451400151 |
7 | 1345616410303 |
oct | 235406772603 |
9 | 60510671674 |
10 | 21141124483 |
11 | 8a69682806 |
12 | 4120153057 |
13 | 1cbbc26c1b |
14 | 1047a8b603 |
15 | 83b026d3d |
hex | 4ec1bf583 |
21141124483 has 2 divisors, whose sum is σ = 21141124484. Its totient is φ = 21141124482.
The previous prime is 21141124423. The next prime is 21141124547. The reversal of 21141124483 is 38442114112.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21141124483 - 217 = 21140993411 is a prime.
It is not a weakly prime, because it can be changed into another prime (21141124423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10570562241 + 10570562242.
It is an arithmetic number, because the mean of its divisors is an integer number (10570562242).
Almost surely, 221141124483 is an apocalyptic number.
21141124483 is a deficient number, since it is larger than the sum of its proper divisors (1).
21141124483 is an equidigital number, since it uses as much as digits as its factorization.
21141124483 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6144, while the sum is 31.
Adding to 21141124483 its reverse (38442114112), we get a palindrome (59583238595).
The spelling of 21141124483 in words is "twenty-one billion, one hundred forty-one million, one hundred twenty-four thousand, four hundred eighty-three".
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