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21141210401 is a prime number
BaseRepresentation
bin10011101100000111…
…010100010100100001
32000120100220202121122
4103230013110110201
5321244122213101
613413453302025
71345620215633
oct235407242441
960510822548
1021141210401
118a69731313
124120194915
131cbbc5706c
141047ab0a53
1583b04251b
hex4ec1d4521

21141210401 has 2 divisors, whose sum is σ = 21141210402. Its totient is φ = 21141210400.

The previous prime is 21141210397. The next prime is 21141210407. The reversal of 21141210401 is 10401214112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14761035025 + 6380175376 = 121495^2 + 79876^2 .

It is a cyclic number.

It is not a de Polignac number, because 21141210401 - 22 = 21141210397 is a prime.

It is a super-3 number, since 3×211412104013 (a number of 32 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 21141210401.

It is not a weakly prime, because it can be changed into another prime (21141210407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10570605200 + 10570605201.

It is an arithmetic number, because the mean of its divisors is an integer number (10570605201).

Almost surely, 221141210401 is an apocalyptic number.

It is an amenable number.

21141210401 is a deficient number, since it is larger than the sum of its proper divisors (1).

21141210401 is an equidigital number, since it uses as much as digits as its factorization.

21141210401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 21141210401 its reverse (10401214112), we get a palindrome (31542424513).

The spelling of 21141210401 in words is "twenty-one billion, one hundred forty-one million, two hundred ten thousand, four hundred one".