Base | Representation |
---|---|
bin | 11110110000111100000… |
… | …011011011111000010001 |
3 | 21111002221110021212222121 |
4 | 132300330003123320101 |
5 | 234114220122140332 |
6 | 4255115113534241 |
7 | 305512101523333 |
oct | 36607403337021 |
9 | 7432843255877 |
10 | 2114131443217 |
11 | 7456640a2382 |
12 | 2a1896414381 |
13 | 124491985321 |
14 | 74478641453 |
15 | 39ed7b61797 |
hex | 1ec3c0dbe11 |
2114131443217 has 2 divisors, whose sum is σ = 2114131443218. Its totient is φ = 2114131443216.
The previous prime is 2114131443167. The next prime is 2114131443241. The reversal of 2114131443217 is 7123441314112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1919931699456 + 194199743761 = 1385616^2 + 440681^2 .
It is a cyclic number.
It is not a de Polignac number, because 2114131443217 - 239 = 1564375629329 is a prime.
It is not a weakly prime, because it can be changed into another prime (2114131443517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057065721608 + 1057065721609.
It is an arithmetic number, because the mean of its divisors is an integer number (1057065721609).
Almost surely, 22114131443217 is an apocalyptic number.
It is an amenable number.
2114131443217 is a deficient number, since it is larger than the sum of its proper divisors (1).
2114131443217 is an equidigital number, since it uses as much as digits as its factorization.
2114131443217 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 16128, while the sum is 34.
Adding to 2114131443217 its reverse (7123441314112), we get a palindrome (9237572757329).
The spelling of 2114131443217 in words is "two trillion, one hundred fourteen billion, one hundred thirty-one million, four hundred forty-three thousand, two hundred seventeen".
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