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2114230004134 = 22345961521829
BaseRepresentation
bin11110110001000001111…
…011011010100110100110
321111010012022202022010221
4132301001323122212212
5234114420340113014
64255132554234554
7305514406343053
oct36610173324646
97433168668127
102114230004134
117457047a0686
122a1903425a5a
131244a9213ab1
147448777a02a
1539ee162eb24
hex1ec41eda9a6

2114230004134 has 8 divisors (see below), whose sum is σ = 3309229571760. Its totient is φ = 1011153480216.

The previous prime is 2114230004113. The next prime is 2114230004153. The reversal of 2114230004134 is 4314000324112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 2114230004099 and 2114230004108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22980760869 + ... + 22980760960.

It is an arithmetic number, because the mean of its divisors is an integer number (413653696470).

Almost surely, 22114230004134 is an apocalyptic number.

2114230004134 is a deficient number, since it is larger than the sum of its proper divisors (1194999567626).

2114230004134 is a wasteful number, since it uses less digits than its factorization.

2114230004134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45961521854.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 2114230004134 its reverse (4314000324112), we get a palindrome (6428230328246).

The spelling of 2114230004134 in words is "two trillion, one hundred fourteen billion, two hundred thirty million, four thousand, one hundred thirty-four".

Divisors: 1 2 23 46 45961521829 91923043658 1057115002067 2114230004134