211431103133 has 2 divisors, whose sum is σ = 211431103134. Its totient is φ = 211431103132.

The previous prime is 211431103127. The next prime is 211431103183. The reversal of 211431103133 is 331301134112.

211431103133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 176960724889 + 34470378244 = 420667^2 + 185662^2 .

It is a cyclic number.

It is not a de Polignac number, because 211431103133 - 2¹⁴ = 211431086749 is a prime.

It is a super-2 number, since 2×211431103133² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211431103099 and 211431103108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211431103183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105715551566 + 105715551567.

It is an arithmetic number, because the mean of its divisors is an integer number (105715551567).

Almost surely, 2^211431103133 is an apocalyptic number.

It is an amenable number.

211431103133 is a deficient number, since it is larger than the sum of its proper divisors (1).

211431103133 is an equidigital number, since it uses as much as digits as its factorization.

211431103133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 211431103133 its reverse (331301134112), we get a palindrome (542732237245).

The spelling of 211431103133 in words is "two hundred eleven billion, four hundred thirty-one million, one hundred three thousand, one hundred thirty-three".