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21143242031 is a prime number
BaseRepresentation
bin10011101100001111…
…000100010100101111
32000120111201222111012
4103230033010110233
5321300132221111
613414005015435
71345643410022
oct235417042457
960514658435
1021143242031
118a6a89974a
1241209b457b
131cbc4b8a02
14104807d1b9
1583b2e448b
hex4ec3c452f

21143242031 has 2 divisors, whose sum is σ = 21143242032. Its totient is φ = 21143242030.

The previous prime is 21143241991. The next prime is 21143242049. The reversal of 21143242031 is 13024234112.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21143242031 is a prime.

It is a super-2 number, since 2×211432420312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21143241988 and 21143242006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21143245031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10571621015 + 10571621016.

It is an arithmetic number, because the mean of its divisors is an integer number (10571621016).

Almost surely, 221143242031 is an apocalyptic number.

21143242031 is a deficient number, since it is larger than the sum of its proper divisors (1).

21143242031 is an equidigital number, since it uses as much as digits as its factorization.

21143242031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 21143242031 its reverse (13024234112), we get a palindrome (34167476143).

The spelling of 21143242031 in words is "twenty-one billion, one hundred forty-three million, two hundred forty-two thousand, thirty-one".