21143405131 has 2 divisors, whose sum is σ = 21143405132. Its totient is φ = 21143405130.

The previous prime is 21143405123. The next prime is 21143405149. The reversal of 21143405131 is 13150434112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 21143405131 - 2³ = 21143405123 is a prime.

It is a super-2 number, since 2×21143405131² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21143405096 and 21143405105.

It is not a weakly prime, because it can be changed into another prime (21143405191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10571702565 + 10571702566.

It is an arithmetic number, because the mean of its divisors is an integer number (10571702566).

Almost surely, 2^21143405131 is an apocalyptic number.

21143405131 is a deficient number, since it is larger than the sum of its proper divisors (1).

21143405131 is an equidigital number, since it uses as much as digits as its factorization.

21143405131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 21143405131 its reverse (13150434112), we get a palindrome (34293839243).

The spelling of 21143405131 in words is "twenty-one billion, one hundred forty-three million, four hundred five thousand, one hundred thirty-one".