Base | Representation |
---|---|
bin | 11110110001001100000… |
… | …101100101001111010100 |
3 | 21111010122012110101222120 |
4 | 132301030011211033110 |
5 | 234120243003110200 |
6 | 4255201523255540 |
7 | 305521546132320 |
oct | 36611405451724 |
9 | 7433565411876 |
10 | 2114400441300 |
11 | 745791a21644 |
12 | 2a195051a5b0 |
13 | 12450561a0a4 |
14 | 744a2264980 |
15 | 3a0015999a0 |
hex | 1ec4c1653d4 |
2114400441300 has 288 divisors, whose sum is σ = 7034483097600. Its totient is φ = 480336099840.
The previous prime is 2114400441277. The next prime is 2114400441317. The reversal of 2114400441300 is 31440044112.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 297673549 + ... + 297680651.
Almost surely, 22114400441300 is an apocalyptic number.
2114400441300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 2114400441300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3517241548800).
2114400441300 is an abundant number, since it is smaller than the sum of its proper divisors (4920082656300).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2114400441300 is a wasteful number, since it uses less digits than its factorization.
2114400441300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7975 (or 7968 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 2114400441300 its reverse (31440044112), we get a palindrome (2145840485412).
The spelling of 2114400441300 in words is "two trillion, one hundred fourteen billion, four hundred million, four hundred forty-one thousand, three hundred".
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