Base | Representation |
---|---|
bin | 1001100111010111111110… |
… | …10110111101110010101011 |
3 | 2202212100122121101010010211 |
4 | 10303223333112331302223 |
5 | 10232411120442210014 |
6 | 112545245503321551 |
7 | 4311416560065151 |
oct | 463537726756253 |
9 | 82770577333124 |
10 | 21144113241259 |
11 | 6812193776108 |
12 | 2455a548b02b7 |
13 | ba4b5c361718 |
14 | 5315482c33d1 |
15 | 26a0184b1cc4 |
hex | 133aff5bdcab |
21144113241259 has 2 divisors, whose sum is σ = 21144113241260. Its totient is φ = 21144113241258.
The previous prime is 21144113241133. The next prime is 21144113241299. The reversal of 21144113241259 is 95214231144112.
It is an a-pointer prime, because the next prime (21144113241299) can be obtained adding 21144113241259 to its sum of digits (40).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21144113241259 - 211 = 21144113239211 is a prime.
It is not a weakly prime, because it can be changed into another prime (21144113241299) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10572056620629 + 10572056620630.
It is an arithmetic number, because the mean of its divisors is an integer number (10572056620630).
Almost surely, 221144113241259 is an apocalyptic number.
21144113241259 is a deficient number, since it is larger than the sum of its proper divisors (1).
21144113241259 is an equidigital number, since it uses as much as digits as its factorization.
21144113241259 is an evil number, because the sum of its binary digits is even.
The product of its digits is 69120, while the sum is 40.
The spelling of 21144113241259 in words is "twenty-one trillion, one hundred forty-four billion, one hundred thirteen million, two hundred forty-one thousand, two hundred fifty-nine".
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