Base | Representation |
---|---|
bin | 11110110001101111111… |
… | …101100010111011110011 |
3 | 21111012012010222201202221 |
4 | 132301233331202323303 |
5 | 234123011043030413 |
6 | 4255341343421511 |
7 | 305542505022532 |
oct | 36615775427363 |
9 | 7435163881687 |
10 | 2115002314483 |
11 | 745a707398a3 |
12 | 2a1a99bb4897 |
13 | 1245a0220476 |
14 | 7451c178319 |
15 | 3a03933768d |
hex | 1ec6ff62ef3 |
2115002314483 has 2 divisors, whose sum is σ = 2115002314484. Its totient is φ = 2115002314482.
The previous prime is 2115002314391. The next prime is 2115002314499. The reversal of 2115002314483 is 3844132005112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2115002314483 - 221 = 2115000217331 is a prime.
It is not a weakly prime, because it can be changed into another prime (2115002314583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057501157241 + 1057501157242.
It is an arithmetic number, because the mean of its divisors is an integer number (1057501157242).
Almost surely, 22115002314483 is an apocalyptic number.
2115002314483 is a deficient number, since it is larger than the sum of its proper divisors (1).
2115002314483 is an equidigital number, since it uses as much as digits as its factorization.
2115002314483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23040, while the sum is 34.
Adding to 2115002314483 its reverse (3844132005112), we get a palindrome (5959134319595).
The spelling of 2115002314483 in words is "two trillion, one hundred fifteen billion, two million, three hundred fourteen thousand, four hundred eighty-three".
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