Base | Representation |
---|---|
bin | 11110110001111101100… |
… | …111001110000110011101 |
3 | 21111012210002221120211210 |
4 | 132301331213032012131 |
5 | 234123443210434010 |
6 | 4255420204335033 |
7 | 305551255521264 |
oct | 36617547160635 |
9 | 7435702846753 |
10 | 2115231343005 |
11 | 746078a49370 |
12 | 2a1b42844479 |
13 | 1246087cc4c1 |
14 | 745407555db |
15 | 3a04e4c7b20 |
hex | 1ec7d9ce19d |
2115231343005 has 64 divisors (see below), whose sum is σ = 3766695229440. Its totient is φ = 1004941036800.
The previous prime is 2115231342971. The next prime is 2115231343007. The reversal of 2115231343005 is 5003431325112.
It is not a de Polignac number, because 2115231343005 - 29 = 2115231342493 is a prime.
It is a super-3 number, since 3×21152313430053 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2115231343007) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2678259 + ... + 3376911.
It is an arithmetic number, because the mean of its divisors is an integer number (58854612960).
Almost surely, 22115231343005 is an apocalyptic number.
It is an amenable number.
2115231343005 is a deficient number, since it is larger than the sum of its proper divisors (1651463886435).
2115231343005 is a wasteful number, since it uses less digits than its factorization.
2115231343005 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 699042.
The product of its (nonzero) digits is 10800, while the sum is 30.
Adding to 2115231343005 its reverse (5003431325112), we get a palindrome (7118662668117).
The spelling of 2115231343005 in words is "two trillion, one hundred fifteen billion, two hundred thirty-one million, three hundred forty-three thousand, five".
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