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2115310306433 is a prime number
BaseRepresentation
bin11110110010000010010…
…100011100010010000001
321111012222121112100022012
4132302002110130102001
5234124123414301213
64255432105022305
7305553234636332
oct36620224342201
97435877470265
102115310306433
117461095817a5
122a1b65184995
1312461bc88b1c
147454b02c289
153a0563c44a8
hex1ec8251c481

2115310306433 has 2 divisors, whose sum is σ = 2115310306434. Its totient is φ = 2115310306432.

The previous prime is 2115310306411. The next prime is 2115310306441. The reversal of 2115310306433 is 3346030135112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2008036370704 + 107273935729 = 1417052^2 + 327527^2 .

It is a cyclic number.

It is not a de Polignac number, because 2115310306433 - 212 = 2115310302337 is a prime.

It is a super-2 number, since 2×21153103064332 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2115310306433.

It is not a weakly prime, because it can be changed into another prime (2115310302433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057655153216 + 1057655153217.

It is an arithmetic number, because the mean of its divisors is an integer number (1057655153217).

Almost surely, 22115310306433 is an apocalyptic number.

It is an amenable number.

2115310306433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2115310306433 is an equidigital number, since it uses as much as digits as its factorization.

2115310306433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19440, while the sum is 32.

The spelling of 2115310306433 in words is "two trillion, one hundred fifteen billion, three hundred ten million, three hundred six thousand, four hundred thirty-three".