Base | Representation |
---|---|
bin | 11110110010000010010… |
… | …100011100010010000001 |
3 | 21111012222121112100022012 |
4 | 132302002110130102001 |
5 | 234124123414301213 |
6 | 4255432105022305 |
7 | 305553234636332 |
oct | 36620224342201 |
9 | 7435877470265 |
10 | 2115310306433 |
11 | 7461095817a5 |
12 | 2a1b65184995 |
13 | 12461bc88b1c |
14 | 7454b02c289 |
15 | 3a0563c44a8 |
hex | 1ec8251c481 |
2115310306433 has 2 divisors, whose sum is σ = 2115310306434. Its totient is φ = 2115310306432.
The previous prime is 2115310306411. The next prime is 2115310306441. The reversal of 2115310306433 is 3346030135112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2008036370704 + 107273935729 = 1417052^2 + 327527^2 .
It is a cyclic number.
It is not a de Polignac number, because 2115310306433 - 212 = 2115310302337 is a prime.
It is a super-2 number, since 2×21153103064332 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2115310306433.
It is not a weakly prime, because it can be changed into another prime (2115310302433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057655153216 + 1057655153217.
It is an arithmetic number, because the mean of its divisors is an integer number (1057655153217).
Almost surely, 22115310306433 is an apocalyptic number.
It is an amenable number.
2115310306433 is a deficient number, since it is larger than the sum of its proper divisors (1).
2115310306433 is an equidigital number, since it uses as much as digits as its factorization.
2115310306433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 32.
The spelling of 2115310306433 in words is "two trillion, one hundred fifteen billion, three hundred ten million, three hundred six thousand, four hundred thirty-three".
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