Base | Representation |
---|---|
bin | 11110110010000100110… |
… | …011110011000100000001 |
3 | 21111020002112010200202002 |
4 | 132302010303303010001 |
5 | 234124220113040031 |
6 | 4255440200233345 |
7 | 305554253004122 |
oct | 36620463630401 |
9 | 7436075120662 |
10 | 2115352080641 |
11 | 746130114338 |
12 | 2a1b7716b855 |
13 | 1246278240a7 |
14 | 745527c4049 |
15 | 3a059dc6ccb |
hex | 1ec84cf3101 |
2115352080641 has 2 divisors, whose sum is σ = 2115352080642. Its totient is φ = 2115352080640.
The previous prime is 2115352080613. The next prime is 2115352080649. The reversal of 2115352080641 is 1460802535112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2115352080625 + 16 = 1454425^2 + 4^2 .
It is a cyclic number.
It is not a de Polignac number, because 2115352080641 - 26 = 2115352080577 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2115352080595 and 2115352080604.
It is not a weakly prime, because it can be changed into another prime (2115352080649) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057676040320 + 1057676040321.
It is an arithmetic number, because the mean of its divisors is an integer number (1057676040321).
Almost surely, 22115352080641 is an apocalyptic number.
It is an amenable number.
2115352080641 is a deficient number, since it is larger than the sum of its proper divisors (1).
2115352080641 is an equidigital number, since it uses as much as digits as its factorization.
2115352080641 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 38.
The spelling of 2115352080641 in words is "two trillion, one hundred fifteen billion, three hundred fifty-two million, eighty thousand, six hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •