Search a number
-
+
21155211311441 is a prime number
BaseRepresentation
bin1001100111101100101001…
…10110101111100101010001
32202220102022001100111101012
410303312110312233211101
510233101333043431231
6112554323033420305
74312261600114664
oct463662466574521
982812261314335
1021155211311441
1168169692a7539
12245803156a695
13ba5c0a6a535c
14531cbc2016db
1526a467973e2b
hex133d94daf951

21155211311441 has 2 divisors, whose sum is σ = 21155211311442. Its totient is φ = 21155211311440.

The previous prime is 21155211311407. The next prime is 21155211311477. The reversal of 21155211311441 is 14411311255112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13110590931025 + 8044620380416 = 3620855^2 + 2836304^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21155211311441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21155211311398 and 21155211311407.

It is not a weakly prime, because it can be changed into another prime (21155211314441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10577605655720 + 10577605655721.

It is an arithmetic number, because the mean of its divisors is an integer number (10577605655721).

Almost surely, 221155211311441 is an apocalyptic number.

It is an amenable number.

21155211311441 is a deficient number, since it is larger than the sum of its proper divisors (1).

21155211311441 is an equidigital number, since it uses as much as digits as its factorization.

21155211311441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4800, while the sum is 32.

Adding to 21155211311441 its reverse (14411311255112), we get a palindrome (35566522566553).

The spelling of 21155211311441 in words is "twenty-one trillion, one hundred fifty-five billion, two hundred eleven million, three hundred eleven thousand, four hundred forty-one".