Base | Representation |
---|---|
bin | 11110110011001101000… |
… | …111011111111111011001 |
3 | 21111100020001211210110011 |
4 | 132303031013133333121 |
5 | 234134211143024303 |
6 | 4300200413521521 |
7 | 305626313253523 |
oct | 36631507377731 |
9 | 7440201753404 |
10 | 2116565204953 |
11 | 7466a2974611 |
12 | 2a22554a32a1 |
13 | 12478bc62224 |
14 | 7462996ca13 |
15 | 3a0cb65616d |
hex | 1eccd1dffd9 |
2116565204953 has 2 divisors, whose sum is σ = 2116565204954. Its totient is φ = 2116565204952.
The previous prime is 2116565204891. The next prime is 2116565204959. The reversal of 2116565204953 is 3594025656112.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1717903033344 + 398662171609 = 1310688^2 + 631397^2 .
It is a cyclic number.
It is not a de Polignac number, because 2116565204953 - 221 = 2116563107801 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2116565204897 and 2116565204906.
It is not a weakly prime, because it can be changed into another prime (2116565204959) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1058282602476 + 1058282602477.
It is an arithmetic number, because the mean of its divisors is an integer number (1058282602477).
Almost surely, 22116565204953 is an apocalyptic number.
It is an amenable number.
2116565204953 is a deficient number, since it is larger than the sum of its proper divisors (1).
2116565204953 is an equidigital number, since it uses as much as digits as its factorization.
2116565204953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944000, while the sum is 49.
The spelling of 2116565204953 in words is "two trillion, one hundred sixteen billion, five hundred sixty-five million, two hundred four thousand, nine hundred fifty-three".
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