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2116634532433 is a prime number
BaseRepresentation
bin11110110011010001001…
…111111101101001010001
321111100101220021222212121
4132303101033331221101
5234134331420014213
64300211331454241
7305631114446461
oct36632117755121
97440356258777
102116634532433
11746729016353
122a2274757381
131247a04268c5
1474634c57ba1
153a0d279c88d
hex1ecd13fda51

2116634532433 has 2 divisors, whose sum is σ = 2116634532434. Its totient is φ = 2116634532432.

The previous prime is 2116634532431. The next prime is 2116634532497. The reversal of 2116634532433 is 3342354366112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1604346490384 + 512288042049 = 1266628^2 + 715743^2 .

It is a cyclic number.

It is not a de Polignac number, because 2116634532433 - 21 = 2116634532431 is a prime.

Together with 2116634532431, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 2116634532433.

It is not a weakly prime, because it can be changed into another prime (2116634532431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1058317266216 + 1058317266217.

It is an arithmetic number, because the mean of its divisors is an integer number (1058317266217).

Almost surely, 22116634532433 is an apocalyptic number.

It is an amenable number.

2116634532433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2116634532433 is an equidigital number, since it uses as much as digits as its factorization.

2116634532433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 933120, while the sum is 43.

Adding to 2116634532433 its reverse (3342354366112), we get a palindrome (5458988898545).

The spelling of 2116634532433 in words is "two trillion, one hundred sixteen billion, six hundred thirty-four million, five hundred thirty-two thousand, four hundred thirty-three".