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2117477103857 is a prime number
BaseRepresentation
bin11110110100000011011…
…110000111100011110001
321111102120121202001120122
4132310003132013203301
5234143043114310412
64300431111020025
7305661025261103
oct36640336074361
97442517661518
102117477103857
11747020693775
122a246a96a615
131248a5b6388b
14746b4b05573
153a131733572
hex1ed037878f1

2117477103857 has 2 divisors, whose sum is σ = 2117477103858. Its totient is φ = 2117477103856.

The previous prime is 2117477103829. The next prime is 2117477103869. The reversal of 2117477103857 is 7583017747112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2087920961296 + 29556142561 = 1444964^2 + 171919^2 .

It is a cyclic number.

It is not a de Polignac number, because 2117477103857 - 222 = 2117472909553 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2117477103799 and 2117477103808.

It is not a weakly prime, because it can be changed into another prime (2117477103817) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1058738551928 + 1058738551929.

It is an arithmetic number, because the mean of its divisors is an integer number (1058738551929).

Almost surely, 22117477103857 is an apocalyptic number.

It is an amenable number.

2117477103857 is a deficient number, since it is larger than the sum of its proper divisors (1).

2117477103857 is an equidigital number, since it uses as much as digits as its factorization.

2117477103857 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304960, while the sum is 53.

The spelling of 2117477103857 in words is "two trillion, one hundred seventeen billion, four hundred seventy-seven million, one hundred three thousand, eight hundred fifty-seven".