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21181153294031 is a prime number
BaseRepresentation
bin1001101000011100111110…
…00111100011011011001111
32202222220020222202202101012
410310032133013203123033
510234013000220402111
6113014253144235435
74314200503251203
oct464163707433317
982886228682335
1021181153294031
11682697092aa75
12246107146bb7b
13ba84b3114303
1453325d712b03
1526ae851b748b
hex13439f1e36cf

21181153294031 has 2 divisors, whose sum is σ = 21181153294032. Its totient is φ = 21181153294030.

The previous prime is 21181153294001. The next prime is 21181153294109. The reversal of 21181153294031 is 13049235118112.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21181153294031 is a prime.

It is a super-2 number, since 2×211811532940312 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 21181153294031.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21181153294001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10590576647015 + 10590576647016.

It is an arithmetic number, because the mean of its divisors is an integer number (10590576647016).

Almost surely, 221181153294031 is an apocalyptic number.

21181153294031 is a deficient number, since it is larger than the sum of its proper divisors (1).

21181153294031 is an equidigital number, since it uses as much as digits as its factorization.

21181153294031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51840, while the sum is 41.

The spelling of 21181153294031 in words is "twenty-one trillion, one hundred eighty-one billion, one hundred fifty-three million, two hundred ninety-four thousand, thirty-one".