211840995853 has 2 divisors, whose sum is σ = 211840995854. Its totient is φ = 211840995852.

The previous prime is 211840995823. The next prime is 211840995859. The reversal of 211840995853 is 358599048112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120105912969 + 91735082884 = 346563^2 + 302878^2 .

It is a cyclic number.

It is not a de Polignac number, because 211840995853 - 2²¹ = 211838898701 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211840995794 and 211840995803.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211840995859) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105920497926 + 105920497927.

It is an arithmetic number, because the mean of its divisors is an integer number (105920497927).

Almost surely, 2^211840995853 is an apocalyptic number.

It is an amenable number.

211840995853 is a deficient number, since it is larger than the sum of its proper divisors (1).

211840995853 is an equidigital number, since it uses as much as digits as its factorization.

211840995853 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3110400, while the sum is 55.

The spelling of 211840995853 in words is "two hundred eleven billion, eight hundred forty million, nine hundred ninety-five thousand, eight hundred fifty-three".