Base | Representation |
---|---|
bin | 1001101000111101011011… |
… | …11110010000010110001101 |
3 | 2210001120020122200021002101 |
4 | 10310132231332100112031 |
5 | 10234304144042242023 |
6 | 113030254434155101 |
7 | 4315355430132466 |
oct | 464365576202615 |
9 | 83046218607071 |
10 | 21198582384013 |
11 | 68332a5123271 |
12 | 2464516422a91 |
13 | baa02cc929c8 |
14 | 5340343a9d6d |
15 | 26b65539c1ad |
hex | 1347adf9058d |
21198582384013 has 2 divisors, whose sum is σ = 21198582384014. Its totient is φ = 21198582384012.
The previous prime is 21198582383989. The next prime is 21198582384029. The reversal of 21198582384013 is 31048328589112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14351997290409 + 6846585093604 = 3788403^2 + 2616598^2 .
It is a cyclic number.
It is not a de Polignac number, because 21198582384013 - 213 = 21198582375821 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21198582394013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10599291192006 + 10599291192007.
It is an arithmetic number, because the mean of its divisors is an integer number (10599291192007).
Almost surely, 221198582384013 is an apocalyptic number.
It is an amenable number.
21198582384013 is a deficient number, since it is larger than the sum of its proper divisors (1).
21198582384013 is an equidigital number, since it uses as much as digits as its factorization.
21198582384013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3317760, while the sum is 55.
The spelling of 21198582384013 in words is "twenty-one trillion, one hundred ninety-eight billion, five hundred eighty-two million, three hundred eighty-four thousand, thirteen".
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