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211995041 is a prime number
BaseRepresentation
bin11001010001011…
…00100110100001
3112202220110112012
430220230212201
5413232320131
633011442305
75152633226
oct1450544641
9482813465
10211995041
11a9736015
125abb6395
1334bc6c6b
142022594d
151392852b
hexca2c9a1

211995041 has 2 divisors, whose sum is σ = 211995042. Its totient is φ = 211995040.

The previous prime is 211995037. The next prime is 211995079. The reversal of 211995041 is 140599112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 210250000 + 1745041 = 14500^2 + 1321^2 .

It is a cyclic number.

It is not a de Polignac number, because 211995041 - 22 = 211995037 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 211994989 and 211995007.

It is not a weakly prime, because it can be changed into another prime (211995841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105997520 + 105997521.

It is an arithmetic number, because the mean of its divisors is an integer number (105997521).

Almost surely, 2211995041 is an apocalyptic number.

It is an amenable number.

211995041 is a deficient number, since it is larger than the sum of its proper divisors (1).

211995041 is an equidigital number, since it uses as much as digits as its factorization.

211995041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3240, while the sum is 32.

The square root of 211995041 is about 14560.0494848060. The cubic root of 211995041 is about 596.2685464948.

The spelling of 211995041 in words is "two hundred eleven million, nine hundred ninety-five thousand, forty-one".