Base | Representation |
---|---|
bin | 10011101111101000… |
… | …000000110111011101 |
3 | 2000201110202022221201 |
4 | 103233220000313131 |
5 | 321404212104432 |
6 | 13423355555501 |
7 | 1350233662651 |
oct | 235750006735 |
9 | 60643668851 |
10 | 21200113117 |
11 | 8a99a02847 |
12 | 4137a5bb91 |
13 | 1ccb20b741 |
14 | 1051844a61 |
15 | 8412c9ee7 |
hex | 4efa00ddd |
21200113117 has 2 divisors, whose sum is σ = 21200113118. Its totient is φ = 21200113116.
The previous prime is 21200113111. The next prime is 21200113199. The reversal of 21200113117 is 71131100212.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19360217881 + 1839895236 = 139141^2 + 42894^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21200113117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21200113094 and 21200113103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21200113111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10600056558 + 10600056559.
It is an arithmetic number, because the mean of its divisors is an integer number (10600056559).
Almost surely, 221200113117 is an apocalyptic number.
It is an amenable number.
21200113117 is a deficient number, since it is larger than the sum of its proper divisors (1).
21200113117 is an equidigital number, since it uses as much as digits as its factorization.
21200113117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 19.
Adding to 21200113117 its reverse (71131100212), we get a palindrome (92331213329).
The spelling of 21200113117 in words is "twenty-one billion, two hundred million, one hundred thirteen thousand, one hundred seventeen".
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