Base | Representation |
---|---|
bin | 11110110110011010100… |
… | …011111111001100111111 |
3 | 21111200010021121020021011 |
4 | 132312122203333030333 |
5 | 234213241033031421 |
6 | 4301530422420051 |
7 | 306110605456033 |
oct | 36663243771477 |
9 | 7450107536234 |
10 | 2120012002111 |
11 | 748101563303 |
12 | 2a2a57891627 |
13 | 124bbb091683 |
14 | 7487563c1c3 |
15 | 3a22e0544e1 |
hex | 1ed9a8ff33f |
2120012002111 has 2 divisors, whose sum is σ = 2120012002112. Its totient is φ = 2120012002110.
The previous prime is 2120012002099. The next prime is 2120012002211. The reversal of 2120012002111 is 1112002100212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2120012002111 - 213 = 2120011993919 is a prime.
It is a super-3 number, since 3×21200120021113 (a number of 38 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2120012002091 and 2120012002100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2120012002211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060006001055 + 1060006001056.
It is an arithmetic number, because the mean of its divisors is an integer number (1060006001056).
Almost surely, 22120012002111 is an apocalyptic number.
2120012002111 is a deficient number, since it is larger than the sum of its proper divisors (1).
2120012002111 is an equidigital number, since it uses as much as digits as its factorization.
2120012002111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 2120012002111 its reverse (1112002100212), we get a palindrome (3232014102323).
The spelling of 2120012002111 in words is "two trillion, one hundred twenty billion, twelve million, two thousand, one hundred eleven".
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