Base | Representation |
---|---|
bin | 110000001101000010010001… |
… | …001101101000010111100110 |
3 | 1000210122012021102110102001112 |
4 | 300031002101031220113212 |
5 | 210241420120113000402 |
6 | 2030520215010025022 |
7 | 62440432511131205 |
oct | 6015022115502746 |
9 | 1023565242412045 |
10 | 212002022000102 |
11 | 616066095a0814 |
12 | 1b93b4b4278172 |
13 | 913a921859719 |
14 | 3a4cd49d8723c |
15 | 19799d476ae52 |
hex | c0d0913685e6 |
212002022000102 has 4 divisors (see below), whose sum is σ = 318003033000156. Its totient is φ = 106001011000050.
The previous prime is 212002022000077. The next prime is 212002022000123. The reversal of 212002022000102 is 201000220200212.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×2120020220001023 (a number of 44 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 53000505500024 + ... + 53000505500027.
It is an arithmetic number, because the mean of its divisors is an integer number (79500758250039).
Almost surely, 2212002022000102 is an apocalyptic number.
212002022000102 is a deficient number, since it is larger than the sum of its proper divisors (106001011000054).
212002022000102 is a wasteful number, since it uses less digits than its factorization.
212002022000102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106001011000053.
The product of its (nonzero) digits is 64, while the sum is 14.
Adding to 212002022000102 its reverse (201000220200212), we get a palindrome (413002242200314).
The spelling of 212002022000102 in words is "two hundred twelve trillion, two billion, twenty-two million, one hundred two", and thus it is an aban number.
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