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2120031211231 is a prime number
BaseRepresentation
bin11110110110011011101…
…101010000111011011111
321111200011121202011020001
4132312123231100323133
5234213310442224411
64301532350235131
7306111230652223
oct36663355207337
97450147664201
102120031211231
1174811139340a
122a2a621b5aa7
13124bc2058b0b
1474877ddc783
153a230a9adc1
hex1ed9bb50edf

2120031211231 has 2 divisors, whose sum is σ = 2120031211232. Its totient is φ = 2120031211230.

The previous prime is 2120031211213. The next prime is 2120031211247. The reversal of 2120031211231 is 1321121300212.

Together with previous prime (2120031211213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2120031211231 - 29 = 2120031210719 is a prime.

It is a super-2 number, since 2×21200312112312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2120031211199 and 2120031211208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2120031211201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060015605615 + 1060015605616.

It is an arithmetic number, because the mean of its divisors is an integer number (1060015605616).

Almost surely, 22120031211231 is an apocalyptic number.

2120031211231 is a deficient number, since it is larger than the sum of its proper divisors (1).

2120031211231 is an equidigital number, since it uses as much as digits as its factorization.

2120031211231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 2120031211231 its reverse (1321121300212), we get a palindrome (3441152511443).

The spelling of 2120031211231 in words is "two trillion, one hundred twenty billion, thirty-one million, two hundred eleven thousand, two hundred thirty-one".