Base | Representation |
---|---|
bin | 110000001101001010101000… |
… | …011001110001100000001111 |
3 | 1000210200001110012000112211221 |
4 | 300031022220121301200033 |
5 | 210242042012223300212 |
6 | 2030524302001024211 |
7 | 62441201150252341 |
oct | 6015125031614017 |
9 | 1023601405015757 |
10 | 212011000993807 |
11 | 6160a3a6a44674 |
12 | 1b94119b325067 |
13 | 913b722b63552 |
14 | 3a4d55c691291 |
15 | 1979d5cb98807 |
hex | c0d2a867180f |
212011000993807 has 2 divisors, whose sum is σ = 212011000993808. Its totient is φ = 212011000993806.
The previous prime is 212011000993777. The next prime is 212011000993871. The reversal of 212011000993807 is 708399000110212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212011000993807 - 27 = 212011000993679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212011000993007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106005500496903 + 106005500496904.
It is an arithmetic number, because the mean of its divisors is an integer number (106005500496904).
Almost surely, 2212011000993807 is an apocalyptic number.
212011000993807 is a deficient number, since it is larger than the sum of its proper divisors (1).
212011000993807 is an equidigital number, since it uses as much as digits as its factorization.
212011000993807 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 43.
The spelling of 212011000993807 in words is "two hundred twelve trillion, eleven billion, nine hundred ninety-three thousand, eight hundred seven".
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