Base | Representation |
---|---|
bin | 110000001101001010101001… |
… | …100110011110100000110011 |
3 | 1000210200001111120212002212202 |
4 | 300031022221212132200303 |
5 | 210242042032400213412 |
6 | 2030524304000013415 |
7 | 62441201513206244 |
oct | 6015125146364063 |
9 | 1023601446762782 |
10 | 212011021101107 |
11 | 6160a407328578 |
12 | 1b9411a600126b |
13 | 913b727083767 |
14 | 3a4d561206ccb |
15 | 1979d5e81b3c2 |
hex | c0d2a999e833 |
212011021101107 has 2 divisors, whose sum is σ = 212011021101108. Its totient is φ = 212011021101106.
The previous prime is 212011021101053. The next prime is 212011021101221. The reversal of 212011021101107 is 701101120110212.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212011021101107 - 216 = 212011021035571 is a prime.
It is a super-2 number, since 2×2120110211011072 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (212011051101107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106005510550553 + 106005510550554.
It is an arithmetic number, because the mean of its divisors is an integer number (106005510550554).
Almost surely, 2212011021101107 is an apocalyptic number.
212011021101107 is a deficient number, since it is larger than the sum of its proper divisors (1).
212011021101107 is an equidigital number, since it uses as much as digits as its factorization.
212011021101107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 20.
Adding to 212011021101107 its reverse (701101120110212), we get a palindrome (913112141211319).
The spelling of 212011021101107 in words is "two hundred twelve trillion, eleven billion, twenty-one million, one hundred one thousand, one hundred seven".
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