Search a number
-
+
212011153 is a prime number
BaseRepresentation
bin11001010001100…
…00100010010001
3112202221021121221
430220300202101
5413233324103
633012045041
75153031214
oct1450604221
9482837557
10212011153
11a9747132
125b003781
1334c013b3
142022b77b
151392d1bd
hexca30891

212011153 has 2 divisors, whose sum is σ = 212011154. Its totient is φ = 212011152.

The previous prime is 212011117. The next prime is 212011169. The reversal of 212011153 is 351110212.

It is an a-pointer prime, because the next prime (212011169) can be obtained adding 212011153 to its sum of digits (16).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126855169 + 85155984 = 11263^2 + 9228^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212011153 is a prime.

It is not a weakly prime, because it can be changed into another prime (212011193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106005576 + 106005577.

It is an arithmetic number, because the mean of its divisors is an integer number (106005577).

Almost surely, 2212011153 is an apocalyptic number.

It is an amenable number.

212011153 is a deficient number, since it is larger than the sum of its proper divisors (1).

212011153 is an equidigital number, since it uses as much as digits as its factorization.

212011153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 212011153 is about 14560.6027691164. The cubic root of 212011153 is about 596.2836519353.

Adding to 212011153 its reverse (351110212), we get a palindrome (563121365).

The spelling of 212011153 in words is "two hundred twelve million, eleven thousand, one hundred fifty-three".