Base | Representation |
---|---|
bin | 1100010101110011101… |
… | …0000110111010001011 |
3 | 202021020111020022121021 |
4 | 3011130322012322023 |
5 | 11433200101242102 |
6 | 241221431453311 |
7 | 21213600255631 |
oct | 3053472067213 |
9 | 667214208537 |
10 | 212012134027 |
11 | 81a063602a1 |
12 | 3510a527237 |
13 | 16cb9b419a5 |
14 | a39357b351 |
15 | 57acce0137 |
hex | 315ce86e8b |
212012134027 has 2 divisors, whose sum is σ = 212012134028. Its totient is φ = 212012134026.
The previous prime is 212012133997. The next prime is 212012134031. The reversal of 212012134027 is 720431210212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212012134027 - 219 = 212011609739 is a prime.
It is a super-2 number, since 2×2120121340272 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 212012133992 and 212012134010.
It is not a weakly prime, because it can be changed into another prime (212012132027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106006067013 + 106006067014.
It is an arithmetic number, because the mean of its divisors is an integer number (106006067014).
Almost surely, 2212012134027 is an apocalyptic number.
212012134027 is a deficient number, since it is larger than the sum of its proper divisors (1).
212012134027 is an equidigital number, since it uses as much as digits as its factorization.
212012134027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 212012134027 its reverse (720431210212), we get a palindrome (932443344239).
The spelling of 212012134027 in words is "two hundred twelve billion, twelve million, one hundred thirty-four thousand, twenty-seven".
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