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212012134027 is a prime number
BaseRepresentation
bin1100010101110011101…
…0000110111010001011
3202021020111020022121021
43011130322012322023
511433200101242102
6241221431453311
721213600255631
oct3053472067213
9667214208537
10212012134027
1181a063602a1
123510a527237
1316cb9b419a5
14a39357b351
1557acce0137
hex315ce86e8b

212012134027 has 2 divisors, whose sum is σ = 212012134028. Its totient is φ = 212012134026.

The previous prime is 212012133997. The next prime is 212012134031. The reversal of 212012134027 is 720431210212.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 212012134027 - 219 = 212011609739 is a prime.

It is a super-2 number, since 2×2120121340272 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 212012133992 and 212012134010.

It is not a weakly prime, because it can be changed into another prime (212012132027) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106006067013 + 106006067014.

It is an arithmetic number, because the mean of its divisors is an integer number (106006067014).

Almost surely, 2212012134027 is an apocalyptic number.

212012134027 is a deficient number, since it is larger than the sum of its proper divisors (1).

212012134027 is an equidigital number, since it uses as much as digits as its factorization.

212012134027 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1344, while the sum is 25.

Adding to 212012134027 its reverse (720431210212), we get a palindrome (932443344239).

The spelling of 212012134027 in words is "two hundred twelve billion, twelve million, one hundred thirty-four thousand, twenty-seven".