Base | Representation |
---|---|
bin | 11110110110100001101… |
… | …000100110001000010111 |
3 | 21111200102112212012110101 |
4 | 132312201220212020113 |
5 | 234214011421310042 |
6 | 4301550301434531 |
7 | 306113546121112 |
oct | 36664150461027 |
9 | 7450375765411 |
10 | 2120130650647 |
11 | 748162531749 |
12 | 2a2a8b56ba47 |
13 | 124c098343c9 |
14 | 748872c5579 |
15 | 3a23968e6b7 |
hex | 1eda1a26217 |
2120130650647 has 2 divisors, whose sum is σ = 2120130650648. Its totient is φ = 2120130650646.
The previous prime is 2120130650587. The next prime is 2120130650719. The reversal of 2120130650647 is 7460560310212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2120130650647 - 215 = 2120130617879 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2120130654647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060065325323 + 1060065325324.
It is an arithmetic number, because the mean of its divisors is an integer number (1060065325324).
Almost surely, 22120130650647 is an apocalyptic number.
2120130650647 is a deficient number, since it is larger than the sum of its proper divisors (1).
2120130650647 is an equidigital number, since it uses as much as digits as its factorization.
2120130650647 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 37.
Adding to 2120130650647 its reverse (7460560310212), we get a palindrome (9580690960859).
The spelling of 2120130650647 in words is "two trillion, one hundred twenty billion, one hundred thirty million, six hundred fifty thousand, six hundred forty-seven".
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