Base | Representation |
---|---|
bin | 1100010101110011111… |
… | …0001010001011010111 |
3 | 202021020120020021100021 |
4 | 3011130332022023113 |
5 | 11433200334232431 |
6 | 241221510330011 |
7 | 21213612301012 |
oct | 3053476121327 |
9 | 667216207307 |
10 | 212013195991 |
11 | 81a06a16153 |
12 | 3510a959907 |
13 | 16cba12417c |
14 | a393776379 |
15 | 57ace4eb11 |
hex | 315cf8a2d7 |
212013195991 has 2 divisors, whose sum is σ = 212013195992. Its totient is φ = 212013195990.
The previous prime is 212013195937. The next prime is 212013196013. The reversal of 212013195991 is 199591310212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212013195991 - 29 = 212013195479 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212013135991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106006597995 + 106006597996.
It is an arithmetic number, because the mean of its divisors is an integer number (106006597996).
Almost surely, 2212013195991 is an apocalyptic number.
212013195991 is a deficient number, since it is larger than the sum of its proper divisors (1).
212013195991 is an equidigital number, since it uses as much as digits as its factorization.
212013195991 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43740, while the sum is 43.
It can be divided in two parts, 2120131 and 95991, that added together give a palindrome (2216122).
The spelling of 212013195991 in words is "two hundred twelve billion, thirteen million, one hundred ninety-five thousand, nine hundred ninety-one".
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