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21201340031 is a prime number
BaseRepresentation
bin10011101111101100…
…101100011001111111
32000201120001122221222
4103233230230121333
5321410020340111
613423442143555
71350250262654
oct235754543177
960646048858
1021201340031
118a9a670623
124138351bbb
131ccb54b021
141051a83c2b
1584146d7db
hex4efb2c67f

21201340031 has 2 divisors, whose sum is σ = 21201340032. Its totient is φ = 21201340030.

The previous prime is 21201340009. The next prime is 21201340051. The reversal of 21201340031 is 13004310212.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21201340031 - 234 = 4021470847 is a prime.

It is a super-2 number, since 2×212013400312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21201339991 and 21201340009.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21201340001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10600670015 + 10600670016.

It is an arithmetic number, because the mean of its divisors is an integer number (10600670016).

Almost surely, 221201340031 is an apocalyptic number.

21201340031 is a deficient number, since it is larger than the sum of its proper divisors (1).

21201340031 is an equidigital number, since it uses as much as digits as its factorization.

21201340031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 21201340031 its reverse (13004310212), we get a palindrome (34205650243).

The spelling of 21201340031 in words is "twenty-one billion, two hundred one million, three hundred forty thousand, thirty-one".