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212019131 is a prime number
BaseRepresentation
bin11001010001100…
…10011110111011
3112202221200120102
430220302132323
5413234103011
633012150015
75153063402
oct1450623673
9482850512
10212019131
11a9752125
125b00830b
1334c04c0c
1420230639
151393073b
hexca327bb

212019131 has 2 divisors, whose sum is σ = 212019132. Its totient is φ = 212019130.

The previous prime is 212019113. The next prime is 212019149. The reversal of 212019131 is 131910212.

Together with previous prime (212019113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (212019113) and next prime (212019149).

It is a cyclic number.

It is not a de Polignac number, because 212019131 - 226 = 144910267 is a prime.

It is a super-2 number, since 2×2120191312 = 89904223819990322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (212019151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106009565 + 106009566.

It is an arithmetic number, because the mean of its divisors is an integer number (106009566).

Almost surely, 2212019131 is an apocalyptic number.

212019131 is a deficient number, since it is larger than the sum of its proper divisors (1).

212019131 is an equidigital number, since it uses as much as digits as its factorization.

212019131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 20.

The square root of 212019131 is about 14560.8767249778. The cubic root of 212019131 is about 596.2911312451.

Adding to 212019131 its reverse (131910212), we get a palindrome (343929343).

The spelling of 212019131 in words is "two hundred twelve million, nineteen thousand, one hundred thirty-one".