Base | Representation |
---|---|
bin | 110000001101010011000001… |
… | …011100111111001001111111 |
3 | 1000210200220201010022111201001 |
4 | 300031103001130333021333 |
5 | 210242213440331414101 |
6 | 2030532352025031131 |
7 | 62441640345615406 |
oct | 6015230134771177 |
9 | 1023626633274631 |
10 | 212020011201151 |
11 | 616131aaa7781a |
12 | 1b942a949254a7 |
13 | 913c52a77889a |
14 | 3a4db751a263d |
15 | 197a1d8bde901 |
hex | c0d4c173f27f |
212020011201151 has 2 divisors, whose sum is σ = 212020011201152. Its totient is φ = 212020011201150.
The previous prime is 212020011201109. The next prime is 212020011201211. The reversal of 212020011201151 is 151102110020212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212020011201151 - 29 = 212020011200639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212020011201751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106010005600575 + 106010005600576.
It is an arithmetic number, because the mean of its divisors is an integer number (106010005600576).
Almost surely, 2212020011201151 is an apocalyptic number.
212020011201151 is a deficient number, since it is larger than the sum of its proper divisors (1).
212020011201151 is an equidigital number, since it uses as much as digits as its factorization.
212020011201151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 19.
Adding to 212020011201151 its reverse (151102110020212), we get a palindrome (363122121221363).
The spelling of 212020011201151 in words is "two hundred twelve trillion, twenty billion, eleven million, two hundred one thousand, one hundred fifty-one".
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