Base | Representation |
---|---|
bin | 11110110110100110010… |
… | …111101101101011100011 |
3 | 21111200122002101012211221 |
4 | 132312212113231223203 |
5 | 234214142242024303 |
6 | 4302002220515511 |
7 | 306115532406412 |
oct | 36664627555343 |
9 | 7450562335757 |
10 | 2120210111203 |
11 | 7481a3374628 |
12 | 2a2ab20abb97 |
13 | 124c201360a2 |
14 | 74893a8b479 |
15 | 3a2416384bd |
hex | 1eda65edae3 |
2120210111203 has 2 divisors, whose sum is σ = 2120210111204. Its totient is φ = 2120210111202.
The previous prime is 2120210111197. The next prime is 2120210111209. The reversal of 2120210111203 is 3021110120212.
It is a balanced prime because it is at equal distance from previous prime (2120210111197) and next prime (2120210111209).
It is a cyclic number.
It is not a de Polignac number, because 2120210111203 - 221 = 2120208014051 is a prime.
It is a super-2 number, since 2×21202101112032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2120210111209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060105055601 + 1060105055602.
It is an arithmetic number, because the mean of its divisors is an integer number (1060105055602).
Almost surely, 22120210111203 is an apocalyptic number.
2120210111203 is a deficient number, since it is larger than the sum of its proper divisors (1).
2120210111203 is an equidigital number, since it uses as much as digits as its factorization.
2120210111203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 2120210111203 its reverse (3021110120212), we get a palindrome (5141320231415).
Subtracting 2120210111203 from its reverse (3021110120212), we obtain a palindrome (900900009009).
The spelling of 2120210111203 in words is "two trillion, one hundred twenty billion, two hundred ten million, one hundred eleven thousand, two hundred three".
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