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212021113 is a prime number
BaseRepresentation
bin11001010001100…
…10111101111001
3112202221210021211
430220302331321
5413234133423
633012203121
75153102233
oct1450627571
9482853254
10212021113
11a9753667
125b0094a1
1334c05aa5
1420231253
151393110d
hexca32f79

212021113 has 2 divisors, whose sum is σ = 212021114. Its totient is φ = 212021112.

The previous prime is 212021099. The next prime is 212021141. The reversal of 212021113 is 311120212.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130804969 + 81216144 = 11437^2 + 9012^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212021113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 212021093 and 212021102.

It is not a weakly prime, because it can be changed into another prime (212021143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106010556 + 106010557.

It is an arithmetic number, because the mean of its divisors is an integer number (106010557).

Almost surely, 2212021113 is an apocalyptic number.

It is an amenable number.

212021113 is a deficient number, since it is larger than the sum of its proper divisors (1).

212021113 is an equidigital number, since it uses as much as digits as its factorization.

212021113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 212021113 is about 14560.9447839074. The cubic root of 212021113 is about 596.2929893248.

Adding to 212021113 its reverse (311120212), we get a palindrome (523141325).

Subtracting 212021113 from its reverse (311120212), we obtain a palindrome (99099099).

The spelling of 212021113 in words is "two hundred twelve million, twenty-one thousand, one hundred thirteen".