Base | Representation |
---|---|
bin | 11110110110110100010… |
… | …000101001101111110111 |
3 | 21111201020022212100210021 |
4 | 132312310100221233313 |
5 | 234220131421003421 |
6 | 4302041303310011 |
7 | 306124362212041 |
oct | 36666420515767 |
9 | 7451208770707 |
10 | 2120443141111 |
11 | 748302967429 |
12 | 2a2b5814b307 |
13 | 124c594b64c9 |
14 | 748b69caa91 |
15 | 3a256d19341 |
hex | 1edb4429bf7 |
2120443141111 has 4 divisors (see below), whose sum is σ = 2165558952672. Its totient is φ = 2075327329552.
The previous prime is 2120443141079. The next prime is 2120443141123. The reversal of 2120443141111 is 1111413440212.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2120443141111 - 25 = 2120443141079 is a prime.
It is a super-2 number, since 2×21204431411112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2120443148111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22557905710 + ... + 22557905803.
It is an arithmetic number, because the mean of its divisors is an integer number (541389738168).
Almost surely, 22120443141111 is an apocalyptic number.
2120443141111 is a deficient number, since it is larger than the sum of its proper divisors (45115811561).
2120443141111 is an equidigital number, since it uses as much as digits as its factorization.
2120443141111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45115811560.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 2120443141111 its reverse (1111413440212), we get a palindrome (3231856581323).
The spelling of 2120443141111 in words is "two trillion, one hundred twenty billion, four hundred forty-three million, one hundred forty-one thousand, one hundred eleven".
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