Base | Representation |
---|---|
bin | 1100010110000101001… |
… | …0101110000100111111 |
3 | 202021102121122120222201 |
4 | 3011201102232010333 |
5 | 11433322414213113 |
6 | 241233020252331 |
7 | 21215452442524 |
oct | 3054122560477 |
9 | 667377576881 |
10 | 212085694783 |
11 | 81a43933606 |
12 | 3512b0a10a7 |
13 | 16ccc159171 |
14 | a39d24914b |
15 | 57b44c0cdd |
hex | 31614ae13f |
212085694783 has 2 divisors, whose sum is σ = 212085694784. Its totient is φ = 212085694782.
The previous prime is 212085694763. The next prime is 212085694801. The reversal of 212085694783 is 387496580212.
212085694783 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212085694783 - 225 = 212052140351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212085694763) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106042847391 + 106042847392.
It is an arithmetic number, because the mean of its divisors is an integer number (106042847392).
It is a 1-persistent number, because it is pandigital, but 2⋅212085694783 = 424171389566 is not.
Almost surely, 2212085694783 is an apocalyptic number.
212085694783 is a deficient number, since it is larger than the sum of its proper divisors (1).
212085694783 is an equidigital number, since it uses as much as digits as its factorization.
212085694783 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5806080, while the sum is 55.
The spelling of 212085694783 in words is "two hundred twelve billion, eighty-five million, six hundred ninety-four thousand, seven hundred eighty-three".
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