Base | Representation |
---|---|
bin | 1001101001010011000101… |
… | …00100011010011001100011 |
3 | 2210002200020110110002122001 |
4 | 10310221202210122121203 |
5 | 10240001443232021011 |
6 | 113035455443424431 |
7 | 4316246404121641 |
oct | 464514244323143 |
9 | 83080213402561 |
10 | 21210202220131 |
11 | 6838218228111 |
12 | 2466819985117 |
13 | bab16243c892 |
14 | 534817708191 |
15 | 26bad55767c1 |
hex | 134a6291a663 |
21210202220131 has 2 divisors, whose sum is σ = 21210202220132. Its totient is φ = 21210202220130.
The previous prime is 21210202220117. The next prime is 21210202220143. The reversal of 21210202220131 is 13102220201212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21210202220131 - 25 = 21210202220099 is a prime.
It is a super-2 number, since 2×212102022201312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21210202220099 and 21210202220108.
It is not a weakly prime, because it can be changed into another prime (21210202260131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10605101110065 + 10605101110066.
It is an arithmetic number, because the mean of its divisors is an integer number (10605101110066).
Almost surely, 221210202220131 is an apocalyptic number.
21210202220131 is a deficient number, since it is larger than the sum of its proper divisors (1).
21210202220131 is an equidigital number, since it uses as much as digits as its factorization.
21210202220131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 21210202220131 its reverse (13102220201212), we get a palindrome (34312422421343).
The spelling of 21210202220131 in words is "twenty-one trillion, two hundred ten billion, two hundred two million, two hundred twenty thousand, one hundred thirty-one".
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