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21210202220131 is a prime number
BaseRepresentation
bin1001101001010011000101…
…00100011010011001100011
32210002200020110110002122001
410310221202210122121203
510240001443232021011
6113035455443424431
74316246404121641
oct464514244323143
983080213402561
1021210202220131
116838218228111
122466819985117
13bab16243c892
14534817708191
1526bad55767c1
hex134a6291a663

21210202220131 has 2 divisors, whose sum is σ = 21210202220132. Its totient is φ = 21210202220130.

The previous prime is 21210202220117. The next prime is 21210202220143. The reversal of 21210202220131 is 13102220201212.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21210202220131 - 25 = 21210202220099 is a prime.

It is a super-2 number, since 2×212102022201312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21210202220099 and 21210202220108.

It is not a weakly prime, because it can be changed into another prime (21210202260131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10605101110065 + 10605101110066.

It is an arithmetic number, because the mean of its divisors is an integer number (10605101110066).

Almost surely, 221210202220131 is an apocalyptic number.

21210202220131 is a deficient number, since it is larger than the sum of its proper divisors (1).

21210202220131 is an equidigital number, since it uses as much as digits as its factorization.

21210202220131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 21210202220131 its reverse (13102220201212), we get a palindrome (34312422421343).

The spelling of 21210202220131 in words is "twenty-one trillion, two hundred ten billion, two hundred two million, two hundred twenty thousand, one hundred thirty-one".