Base | Representation |
---|---|
bin | 1100010110001010111… |
… | …1110100101010010111 |
3 | 202021111022120120012222 |
4 | 3011202233310222113 |
5 | 11433400141214033 |
6 | 241235251332555 |
7 | 21216200053223 |
oct | 3054257645227 |
9 | 667438516188 |
10 | 212110101143 |
11 | 81a56693456 |
12 | 351372b115b |
13 | 170042230b5 |
14 | a3a259d783 |
15 | 57b66e2598 |
hex | 3162bf4a97 |
212110101143 has 2 divisors, whose sum is σ = 212110101144. Its totient is φ = 212110101142.
The previous prime is 212110101109. The next prime is 212110101163. The reversal of 212110101143 is 341101011212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212110101143 - 210 = 212110100119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212110101163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106055050571 + 106055050572.
It is an arithmetic number, because the mean of its divisors is an integer number (106055050572).
Almost surely, 2212110101143 is an apocalyptic number.
212110101143 is a deficient number, since it is larger than the sum of its proper divisors (1).
212110101143 is an equidigital number, since it uses as much as digits as its factorization.
212110101143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 212110101143 its reverse (341101011212), we get a palindrome (553211112355).
The spelling of 212110101143 in words is "two hundred twelve billion, one hundred ten million, one hundred one thousand, one hundred forty-three".
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