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2121113132233 is a prime number
BaseRepresentation
bin11110110111011100001…
…100011101110011001001
321111202222000120102211021
4132313130030131303021
5234223014430212413
64302231555432441
7306150106066654
oct36673414356311
97452860512737
102121113132233
1174861707a6a7
122a31045b5721
13125035249864
147493b99289b
153a295a6018d
hex1eddc31dcc9

2121113132233 has 2 divisors, whose sum is σ = 2121113132234. Its totient is φ = 2121113132232.

The previous prime is 2121113132227. The next prime is 2121113132309. The reversal of 2121113132233 is 3322313111212.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1921958004409 + 199155127824 = 1386347^2 + 446268^2 .

It is a cyclic number.

It is not a de Polignac number, because 2121113132233 - 225 = 2121079577801 is a prime.

It is a super-3 number, since 3×21211131322333 (a number of 38 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2121113132198 and 2121113132207.

It is not a weakly prime, because it can be changed into another prime (2121113132533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060556566116 + 1060556566117.

It is an arithmetic number, because the mean of its divisors is an integer number (1060556566117).

Almost surely, 22121113132233 is an apocalyptic number.

It is an amenable number.

2121113132233 is a deficient number, since it is larger than the sum of its proper divisors (1).

2121113132233 is an equidigital number, since it uses as much as digits as its factorization.

2121113132233 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1296, while the sum is 25.

Adding to 2121113132233 its reverse (3322313111212), we get a palindrome (5443426243445).

The spelling of 2121113132233 in words is "two trillion, one hundred twenty-one billion, one hundred thirteen million, one hundred thirty-two thousand, two hundred thirty-three".