Base | Representation |
---|---|
bin | 11110110111011100101… |
… | …010011111001001110111 |
3 | 21111202222120101021020221 |
4 | 132313130222133021313 |
5 | 234223023434031403 |
6 | 4302232440235211 |
7 | 306150233015125 |
oct | 36673452371167 |
9 | 7452876337227 |
10 | 2121121002103 |
11 | 748620565424 |
12 | 2a310716bb07 |
13 | 125036a7399c |
14 | 7493ca40915 |
15 | 3a2965b6dbd |
hex | 1eddca9f277 |
2121121002103 has 2 divisors, whose sum is σ = 2121121002104. Its totient is φ = 2121121002102.
The previous prime is 2121121002031. The next prime is 2121121002113. The reversal of 2121121002103 is 3012001211212.
Together with previous prime (2121121002031) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2121121002103 - 221 = 2121118904951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2121121002113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060560501051 + 1060560501052.
It is an arithmetic number, because the mean of its divisors is an integer number (1060560501052).
Almost surely, 22121121002103 is an apocalyptic number.
2121121002103 is a deficient number, since it is larger than the sum of its proper divisors (1).
2121121002103 is an equidigital number, since it uses as much as digits as its factorization.
2121121002103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 2121121002103 its reverse (3012001211212), we get a palindrome (5133122213315).
The spelling of 2121121002103 in words is "two trillion, one hundred twenty-one billion, one hundred twenty-one million, two thousand, one hundred three".
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